-3x^2-24x=-195

Solution for -3x^2-24x=-195 equation:

-3x^2-24x=-195

We move all terms to the left:

-3x^2-24x-(-195)=0

We add all the numbers together, and all the variables

-3x^2-24x+195=0

a = -3; b = -24; c = +195;
Δ = b2-4ac
Δ = -242-4·(-3)·195
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-54}{2*-3}=\frac{-30}{-6}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+54}{2*-3}=\frac{78}{-6}
=-13
$